Categories
1. Simple Harmonic Motion

Kinetic Energy of a Particle in SHM

Kinetic Energy = 1/2​mv2 [Since,v2=A2ω2cos2(ωt+ϕ)]

1/2mω2A2cos2(ωt+ϕ)

1/2mω2(A2−x2)

Therefore, the Kinetic Energy = 1/2​mω2A2cos2(ωt+ϕ)=1/2​mω2(A2−x2)

Leave a Reply

Your email address will not be published. Required fields are marked *